Calculate the area of triangle ABC with the following vertices A(1, 3, 0) B (0, 2, 5) and C (-1, 0, 2) In radical form.

The formula that contains radical and it gives the area of
a triangle is called Heron's formula.

S =
sqrt[p(p-a)(p-b)(p-c)]

p = half perimeter of
triangle

p = (a+b+c)/2

a,b,c
are the lengths of the sides of triangle

a = sqrt[(xC -
xB)^2 + (yC - yB)^2]

a = sqrt(1 +
4)

a = sqrt5

b = sqrt[(xC -
xA)^2 + (yC - yA)^2]

b = sqrt(4 +
9)

b = sqrt13

c = sqrt[(xA -
xB)^2 + (yA - yB)^2]

c = sqrt(1 +
1)

c = sqrt2

S =
sqrt{[(sqrt2+sqrt5+sqrt13)/2]*((sqrt2+sqrt5+sqrt13)/2-sqrt5)*((sqrt2+sqrt5+sqrt13)/2-sqrt13)*((sqrt2+sqrt5+sqrt13)/2-sqrt2)]}

S
=
sqrt{[(sqrt2+sqrt5+sqrt13)/2]*[(sqrt2-sqrt5+sqrt13)/2]*[(sqrt2+sqrt5-sqrt13)/2]*[(-sqrt2+sqrt5+sqrt13)/2]

S
=
{sqrt[(sqrt2+sqrt5+sqrt13)*(sqrt2-sqrt5+sqrt13)*(sqrt2+sqrt5-sqrt13)*(-sqrt2+sqrt5+sqrt13)]}/4