Solve the following: ((x-9)^.5 ) + 1 = x^.5I''m using the ^ to indicate take the item before to the power after the ^. This means to take...

Consider srqrt(x) as the square root of
x.

We
have:

sqrt(x-9) + 1 = sqrt(x) :: taking both side to the
power of 2

[sqrt(x-9) + 1]^2 =
[sqrt(x)]^2

(x-9) + 2*[sqrt(x-9)*1] + 1 = x :: subtracting
x on both sides

2*[sqrt(x-9)] - 8 = 0 :: adding 8 to both
sides and dividing by 2

sqrt(x-9) = 4 :: taking both sides
to the power of 2

x-9 = 16 :: adding 9 to both
sides

x = 25

hope
that helps =)