A die is thrown twice. What is the probability that the sum of the number of dots is 4 or 10?

We will create the following table to sort out the
problem

FIRST DICE
-------->

1|   2|   3|   4|   5|  
6

--------------------------------------------

1
|              2|  3|   4|   5|   6|    7

2 |            
 3|  4|   5|   6|   7|    8

3 |              4|  5|   6|  
7|   8|    9

4 |              5|  6|   7|   8|   9|  
10

5 |              6|  7|   8|   9| 10|  
11

6 |              7|  8|   9| 10| 11|  
12

From this table we can get the sum
of the two dots in both cases.

thus, all possible outcome =
 36

favourable outcome =  3 + 3
=6

probability = 6/36 =
1/6(Ans.)