How many moles of Na3C6H5O7 can be produced if one tablet containing 0.0267 mol of NaHCO3 is dissolved? When an antacid tablet dissolves in water,...

To solve this problem look at the equation of the chemical
reaction that takes place between the antacid which is sodium bicarbonate and citric
acid:

3 NaHCO3 + H3C6H5O7 --> 3 CO2 + 3 H2O +
Na3C6H5O7

We see that 3 molecules of NaHCO3 react with one
molecule of citric acid to give one molecule of sodium citrate or Na3C6H5O7 in the final
products.

When one tablet of NaHCO3  containing 0.0267 mole
of the compound reacts with citric acid the number of moles of Na3C6H5O7 produced is one
third the number of moles of NaHCO3 that reacted
originally.

This is equal to 0.0267/3 = 0.0089
moles

When 0.0267 moles of NaHCO3 are
dissolved we get 0.0089 moles of Na3C6H5O7.