Solve using the quadratic formula:3x^2 - 4x + 3 = 0

Given the quadratic
equation:

3x^2 - 4x + 3 = 0

We
will use the quadratic formula to solve for x.

==> x
= [ -b + sqrt(b^2-4ac)]/2a

==> a = 3     b= -4    
c= 3

==> x1= [
4+sqrt(16-4*3*3)]/2*3

             = [ 4+ sqrt(-20) /
6

              = 4+ 2sqrt5*i)/
6

              = ( 2+
sqrt5*i)/3

==> x2=
(2-sqrt5*i)/3

Then we have two complex
roots.

==> x = { (2+sqrt5*i)/3  ,   
(2-sqrt5*i)/3  }