What is the volume of a gas at standard temperature if the gas occupies 3.65L at 25 Celsius?

The standard conditions in chemistry refer to a
temperature of 273 K or 0 Celsius and a pressure if 1
atm.

Here the volume of the gas at 25 Celsius is 3.65 l.
Use the Ideal Gas Law which gives P*V = n*R*T where P is the pressure, V is the volume,
n is the number of moles of the gas, R is a constant and T is the
temperature.

Here we know V = 3.65 at 298
K

P*3.65 = n*R*298

=>
3.65/298 = n*R/P = a constant which we can denote by k

At
the standard temperature of 273 K, let the volume be
V

V/273 = k =
3.65/298

=> V =
3.65*273/298

=> V =
3.343

The volume of the gas at standard
temperature is 3.343 l