We can use mathematical induction for
this.
P(n) = 5^n - 5
When
n=1;
p(1) = 5^1-5 = 0=0/4 ; this is divisible by
4.
Let us assume a positive integer p
where
p(p) = 5^p-5
We assume
this is divisible by 4.
So we can
write;
p(p)=(5^p-5) =
4k------(1)
where k is a positive
integer.
so p(p) = 4k
Then
consider n=p+1
p(p+1) =
5^(p+1)-5------(2)
We must show equation (2) is
divisible by 4.
Then p(p+1)=4q where q is a positive
integer.
(1)*5
5p(p) =
5(5^p-5)
=
5^(p+1)-25
=
[5^(p+1)-5]-20
5p(p) =
[5^(p+1)-5]-20
5*4k =
p(p+1)-20
p(p+1) = 5*4k-20=4(5k-5) =
4q
So when n=p+1 p(n) is divisible by
4.
So for all positive n p(n) is divisible by
4.
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