What is the result of fractions sumation 2x/(x^2-4)-3/(x-2)(x+2)+2/(x+2) ?

We need the result of :
2x/(x^2-4)-3/(x-2)(x+2)+2/(x+2)

2x/(x^2-4)-3/(x-2)(x+2)+2/(x+2)

first
make the denominator the same for all the terms

=>
2x/(x -2)(x + 2) - 3/(x-2)(x+2) + 2(x - 2)/(x+2)(x -
2)

=> [2x - 3 + 2(x - 2)]/(x - 2)(x +
2)

=> [2x - 3 + 2x - 4]/(x - 2)(x +
2)

=> (4x - 7)/(x - 2)(x +
2)

The result is (4x - 7)/(x - 2)(x +
2)