How far will the car slide once the brakes are applied and it comes to a stop in the following case:A 14,700 N car is traveling at 25 m/s and then...

The car is initially traveling at 25 m/s. When the brakes
are applied there is a resistive force that leads to a decrease in the velocity of the
car and it eventually comes to a stop. The weight of the car is given as 14700 N. The
average braking force between the tires and the road is 7100
N.

The mass of the car is 14700/9.8. The deceleration due
to the braking force is 7100/ (14700/9.8) = (7100*9.8)/14700 m/s^2 = 71/15
m/s^2.

The distance traveled by the car while its velocity
decreases from 25 m/s to 0 m/s due the deceleration of 4.73 m/s^2 is given by
:

d = (v^2 - u^2)/2a

=>
(0 - 25^2)/2*(-71/15)

=>
(25^2*15)/(2*71)

=> 66.02
m

The car slides a distance of 66.02 m before it comes to a
halt.