Find the derivative of f(x) = (x^2-3x+2)*ln x

Given f(x) = (x^2 - 3x + 2) * ln
x

We will use the product rule to find the
derivative.

Let f(x) = u*v such
that:

u= x^2 -3x + 2  ==> u' =
2x-3

v = ln x ===>    v' =
1/x

==> f'(x) = u'*v +
u*v'

==> f'(x) = ( 2x-3)*lnx + (x^2 - 3x +
2)*1/x

==> f'(x) = (2x-3)ln x + (x -3 +
2/x)

==> f'(x) = (2x-3)lnx + x + 2/x -
3