In what quadrant does the curve y= x^2 -5x+3 meets the curve y= 2x^2 -3x +4

Given the curve y= x^2 - 5x + 3 and the curve y= 2x^2 - 3x
+ 4

We need to find the position of the intersection
point.

First we will determine the coordinates of the
intersection points.

==> 2x^2 - 3x + 4 = x^2 - 5x +
3

==> x^2 + 2x + 1 =
0

==> We will
factor.

==> (x+1)^2 =
0

==> x= -1 ==> y=
9

Then the intersection point is (-1,
9)

The point ( -1, 9) is located into the second
quadrant.

Then the curves meet in the second
quadrant.